Mission: Yozakura Family Feats (2024)

Contents

  • 1 Goliath's Attack
  • 2 Kyoichiro Lifts Rocks
  • 3 Momo's Bombs
  • 4 Shinzo's Attack
  • 5 Momo's Explosion
  • 6 Hifumi and Futaba Punch a Hole in the Sea
  • 7 Futaba Reflects Flame

Goliath's Attack[]

Goliath's attack creates a massive explosion next to Yozakura Mansion.

Diameter of Explosion: 91.5 m

Radius of Explosion: 45.75 m

W = R^3*((27136*P+8649)^(1/2)/13568-93/13568)^2

W = 45.75^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2

W = 7.7 Tons (Large Building level+)

Kyoichiro Lifts Rocks[]

Mission: Yozakura Family Feats (1)The total amount of rock is cut off, but I'm going to assume he lifted in a rectangular shape. It seems to be just one layer of rocks. The perspective makes it hard to see the actual thickness of the layer, so I'll just assume its 1 meter.

76 m * 45.9 m * 1 m = 3488.4 m3 = 3.488e+9 cm3

Most rocks have a density of between 2.6 and 2.7 g/cc. This gives us a density of 9068800000 g, or 9068800 kg.

Ep = M*g*h

9068800 * 9.81 * 15.6 = 1387852876.8 joules = 0.33 tons of tnt (Building level)

Momo's Bombs[]

Mission: Yozakura Family Feats (2)Mission: Yozakura Family Feats (3)Mission: Yozakura Family Feats (4)

So, Momo Yozakura has placed bombs that he claims are capable of vaporizing everything in a 100 meter radius. This presents a problem, as we don't really know what he means by this. The base is underground, so at most he would be vaporizing a 100 meter radius sphere. The problem is that he detonated a bomb and it didn't seem to be that catastrophic on its on, while the potential damage to the city caused by all of them detonating doesn't seem to line up with kilometers beneath it being vaporized. So, I will do two ends: a low end assuming "vaporization" is just hyperbole," and a high end taking it literally.

Mid End:

Pretty basic, we just use an explosion formula. Since it does say vaporization, I will assume the highest psi listed by this website, 29 psi, or 1.99948 bars. These are explosions from the ground, so we will use this formula:

W = R^3*((27136*P+8649)^(1/2)/13568-93/13568)^2

W = 100^3*((27136*1.37895+8649)^(1/2)/13568-93/13568)^2

W = 80.3684356986 tons of tnt (City Block level+)

High End:

A 100 meter radius sphere would have a volume of 4.19e+12 cubic centimeters.

Energy for vaporization is 25700 joules/cc.

4.19e+12 * 25700 = 1.07683e+17 joules = 25.7 megatons (City level)

In my opinion, the first end is far more reliable and almost certainly more in line with what the author intended. City level seems like a massive outlier.

Shinzo's Attack[]

The water displacement of the ship is 20,000 tons, so I will use this recent 20,000 ton Destroyer built by the Japanese navy, which has a length of 690 feet or 210 meters.

Mission: Yozakura Family Feats (5)Mission: Yozakura Family Feats (6)

The thickness of a Destroyer hull is generally about 3 cm. With the radius of the hole being 10 meters, or 1000 cm.

V = πr2h

V = 9.42e+6 cm3

Looking at the size of the rubble, I will use violent fragmentation of steel, so 568.5 J/cc.

9.42e+6*568.5 = 5.35527e+9 joules = 1.28 tons (Building level+)

Momo's Explosion[]

Mission: Yozakura Family Feats (7)

This feat involves the same ship as the previous feat, so we can use the same measurements. This gives us a height of 20 meters and a width of 26.5 meters. Referring to the previous source on the size of a ship, the 20,000 ton ship has a beam (width) of 39.6 meters.

39.6*20*26.5 = 20988 m3 = 2.0988e+10 cm3

Given how thin the hull is, I'll estimate a hollowness of 98%.

2.0988e+10 * .02 = 4.1976e+8

I'll again be using violent fragmentation, so:

4.1976e+8 * 568.5 = 2.3863356e+11 joules = 57.03 tons of tnt (City Block level+)

Hifumi and Futaba Punch a Hole in the Sea[]

Futaba helps Hifumi with the accuracy of her attack, and together they destroy a submarine 30 klicks away, leaving a huge hole in the sea.

Mission: Yozakura Family Feats (8)

Radius: 15.25 meters

Length: 30 klicks 30000 meters

Volume: 2.19e+7 m3

Density of water is 997 kg/m3

Mass: 2.18343e10 kg

Omnidirectional KE = 1/12 * cloud mass * (Speed of movement in m/s)2

KE = (1/12)*2.18343e10*(15.25)^2

KE = 4.23153282813e+11 joules = 101 tons of tnt (Multi-City Block level)

Futaba Reflects Flame[]

During her fight with Akai, Futaba counters a large burst of flame that shoots out above the mountain

The base is stated to be 1000 meters long, and using the diagram shown, we get the following sizes:

Base Depth: 1000 m

Mountain Height: 147 m

Flame Height: 447 m

Flame Width: 69 m

V=πr2h

V=π692447

V=6.69e6

For the heat of the flame, Akai said she will grow hot enough to turn Futaba to flame. She was also at risk of turning to ash herself. So, I will use a temperature of 3000 degrees fahrenheit, or 1648.889 celsius. Interestingly, this also seems to be the heat of flamethrower flames, although I don't know how reliable of a source that is. Regardless, considering the fact that the flames she wielded were explicitly incredibly hot and condensed, this seems to be a good high end. As a low end, I will use 1200 C.

I used this calculator. For pressure, input 1.103 Bar for sea level. Specific gas constant of air is 287.05 J*kg*kelvin. Then input the temperature of the fire and you'll get the density of the fire. This gives us a density of 0.2 kg/m3 with 1648 C or 0.26 kg/m3 with 1200 C.

6.69e6 (volume) * 0.2 = 1338000 kg

Heat Capacity of air is 929 j/kg

Average temp is 16 degrees Celsius

Using this formula

Low End: 1739400 * 929 * 1184 = 1.9132287e+12 joules = 457 tons of tnt (Multi-City Block level)

High End: 1338000 * 929 * 1400 = 3.709118e+12 joules = 886 tons of tnt (Multi-City Block level+)

Mission: Yozakura Family Feats (2024)
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